/** * Copyright (c) 2021 OpenLens Authors * * Permission is hereby granted, free of charge, to any person obtaining a copy of * this software and associated documentation files (the "Software"), to deal in * the Software without restriction, including without limitation the rights to * use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of * the Software, and to permit persons to whom the Software is furnished to do so, * subject to the following conditions: * * The above copyright notice and this permission notice shall be included in all * copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS * FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR * COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER * IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN * CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE. */ /** * This function splits an array into two sub arrays on the first instance of * element (from the left). If the array does not contain the element. The * return value is defined to be `[array, [], false]`. If the element is in * the array then the return value is `[left, right, true]` where `left` is * the elements of `array` from `[0, index)` and `right` is `(index, length)` * @param array the full array to split into two sub-arrays * @param element the element in the middle of the array * @returns the left and right sub-arrays which when conjoined with `element` * is the same as `array`, and `true` */ export function splitArray(array: T[], element: T): [T[], T[], boolean] { const index = array.indexOf(element); if (index < 0) { return [array, [], false]; } return [array.slice(0, index), array.slice(index + 1, array.length), true]; } /** * Splits an array into two parts based on the outcome of `condition`. If `true` * the value will be returned as part of the right array. If `false` then part of * the left array. * @param src the full array to bifurcate * @param condition the function to determine which set each is in */ export function bifurcateArray(src: T[], condition: (item: T) => boolean): [falses: T[], trues: T[]] { const res: [T[], T[]] = [[], []]; for (const item of src) { res[+condition(item)].push(item); } return res; }